Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
337 views
in Technique[技术] by (71.8m points)

java - How to get parametrized Class instance

Since generics were introduced, Class is parametrized, so that List.class produces Class<List>. This is clear.

What I am not able to figure out is how to get a instance of Class of type which is parametrized itself, i.e. Class<List<String>>. Like in this snippet:

public class GenTest {
    static <T> T instantiate(Class<T> clazz) throws Exception {
        return clazz.newInstance();
    }
    public static void main(String[] args) throws Exception {
        // Is there a way to avoid waring on the line below
        // without using  @SuppressWarnings("unchecked")?
        // ArrayList.class is Class<ArrayList>, but I would like to
        // pass in Class<ArrayList<String>>
        ArrayList<String> l = GenTest.instantiate(ArrayList.class);
    }
}

I run into variations of this problem quite often and I still don't know, if I just miss something, or if there is really no better way. Thanks for suggestions.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The Class class is a run-time representation of a type. Since parametrized types undergo type erasure at runtime, the class object for Class would be the same as for Class<List<Integer>> and Class<List<String>>.

The reason you cannot instantiate them using the .class notation is that this is a special syntax used for class literals. The Java Language Specification specifically forbids this syntax when the type is parametrized, which is why List<String>.class is not allowed.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...