I have a data model like so
public class NewsItem
{
public virtual int Id { get; set; }
public virtual string NewsTitle { get; set; }
public virtual string NewsContent { get; set; }
public virtual byte[] NewsImage { get; set; }
public virtual DateTime DateAdded { get; set; }
public virtual bool IsLive { get; set; }
}
I then display this data through a View like so:
@model BusinessObject.Domain.NewsItem
<div class="row-fluid">
<h3>
@Html.ValueFor(model => model.NewsTitle)
</h3>
<div class="span5">
<img src="~/Content/images/stock.jpg" />
</div>
<div class="span7">
<p>
@Html.ValueFor(model => model.DateAdded)
</p>
<p>
@Html.ValueFor(model => model.NewsContent)
</p>
</div>
</div>
I then save the data using the _db.SaveChanges() in my controller like so:
[Authorize]
[HttpPost]
public ActionResult Create(CreateNewsViewModel input)
{
if (ModelState.IsValid)
{
var news = new NewsItem();
news.NewsTitle = input.nTitle;
news.NewsContent = input.nContent;
news.DateAdded = input.nDateAdded;
news.IsLive = input.nIsLive;
Mydb data = new Mydb();
data.NewsItems.Add(news);
data.SaveChanges();
return View("Index", data.NewsItems);
}
else
{
return View(input);
}
}
Currently I don't have an image upload bit. How would I go about this? In my db I have a binary field, and my data type in my object is a byte[]. But I don't know where I need to handle the Image Upload?
Do I need a seperate action that returns the view? Some pointers on this would be grand.
Cheers
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