You could do it by (implicitly) using datetime.timedelta
to calculate a "Gregorian" timestamp that would be valid for dates from 1582-Oct-15 to the present (or some other "epoch" you would like to use).
As the function's docstring indicates, date strings will, by default, be parsed using a '%Y-%m-%d'
strptime
-like format string parameter, but that can be overridden.
from datetime import datetime
GREGORIAN_EPOCH = datetime.strptime('1582-10-15', '%Y-%m-%d')
def gregorian_timestamp(date, format='%Y-%m-%d'):
""" Calculate timestamp using start of Gregorian calender as epoch.
The date parameter can be either a string or a datetime.datetime
object. Strings will be parsed using the '%Y-%m-%d' format by default
unless a different one is specfied via the optional format parameter.
"""
try:
date = datetime.strptime(date, format)
except TypeError:
pass
return (date - GREGORIAN_EPOCH).total_seconds() # The timedelta in seconds.
if __name__ == '__main__':
current_date = datetime.now()
timestamp = gregorian_timestamp(current_date)
print('gregorian timestamp:', timestamp) # -> gregorian timestamp: 13768250461.136208
timestamp = gregorian_timestamp('1970-01-01')
print('gregorian timestamp:', timestamp) # -> gregorian timestamp: 12219292800.0
timestamp = gregorian_timestamp('1955-02-28')
print('gregorian timestamp:', timestamp) # -> gregorian timestamp: 11750918400.0
timestamp = gregorian_timestamp('1582-10-15')
print('gregorian timestamp:', timestamp) # -> gregorian timestamp: 0.0
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