Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
374 views
in Technique[技术] by (71.8m points)

c# - The deserializer has no knowlege of any type that maps to this contract

I'm trying to serialize and deserialize a tree of Node objects. My abstract "Node" class as well as other abstract and concrete classes that derive from it are defined in my "Informa" project. In addition, I've created a static class in Informa for serialization / deserialization.

First I'm deconstructing my tree into a flat list of type Dictionary(guid,Node) where guid is the unique id of Node.

I am able to serialize all my Nodes with out a problem. But when I try to deserialize I get the following exception.

Error in line 1 position 227. Element 'http://schemas.microsoft.com/2003/10/Serialization/Arrays:Value' contains data of the 'Informa:Building' data contract. The deserializer has no knowlege of any type that maps to this contract. Add the type corresponding to 'Building' to the list of known types - for example, by usying the KnownTypeAttribute or by adding it to the list of known types passed to DataContract Serializer.

All classes that derive from Node, including Building, have the [KnownType(typeof(type t))] attribute applied to them.

My serialization and deserialization methods are below:

public static void SerializeProject(Project project, string filePath)
{
    try
    {
        Dictionary<Guid, Node> nodeDic = DeconstructProject(project);

        Stream stream = new FileStream(filePath, FileMode.Create, FileAccess.Write, FileShare.None);

        //serialize

        DataContractSerializer ser = new DataContractSerializer(typeof(Dictionary<Guid, Node>),"InformaProject","Informa");

        ser.WriteObject(stream,nodeDic);

        // Cleanup
        stream.Close();
    }
    catch (Exception e)
    {
        MessageBox.Show("There was a problem serializing " + Path.GetFileName(filePath) + ". 

Exception:" + e.Message, "Doh!", MessageBoxButtons.OK, MessageBoxIcon.Error);
        throw e;
    }

}



public static Project DeSerializeProject(string filePath)
{
    try
    {
        Project proj;

        // Read the file back into a stream
        Stream stream = new FileStream(filePath, FileMode.Open, FileAccess.Read, FileShare.Read);

        DataContractSerializer ser = new DataContractSerializer(typeof(Dictionary<Guid, Node>), "InformaProject", "Informa");

        Dictionary<Guid, Node> nodeDic = (Dictionary<Guid, Node>)ser.ReadObject(stream);

        proj = ReconstructProject(nodeDic);        

        // Cleanup
        stream.Close();

        return proj;

    }
    catch (Exception e)
    {
        MessageBox.Show("There was a problem deserializing " + Path.GetFileName(filePath) + ". 

Exception:" + e.Message, "Doh!", MessageBoxButtons.OK, MessageBoxIcon.Error);
        return null;
    }

}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

All classes that derive from Node, including Building, have the [KnownType(typeof(type t))] attribute applied to them.

KnownType is usually applied to the base type - i.e.

[DataContract, KnownType(typeof(Building)), ...]
abstract class Node { ... }

(note - you can also specify the known-types in the DataContractSerializer constructor, without requiring attributes)

EDIT RE YOUR REPLY

If the framwork class doesn't know about all the derived types, then you need to specify the known types when creating the serializer:

[DataContract] abstract class SomeBase { }
[DataContract] class Foo : SomeBase { }
[DataContract] class Bar : SomeBase { }
...
// here the knownTypes argument is important
new DataContractSerializer(typeof(SomeBase),
      new Type[] { typeof(Foo), typeof(Bar) });

This can be combined with (for example) preserveObjectReferences etc by replacing the null in the previous example.

END EDIT

However, without something reproducible (i.e. Node and Building), it is going to be hard to help much.

The other odd thing; trees structures are very well suited to things like DataContractSerializer - there is usually no need to flatten them first, since trees can be trivially expressed in xml. Do you really need to flatten it?


Example:

using System;
using System.Collections.Generic;
using System.IO;
using System.Runtime.Serialization;
using System.Xml;

[DataContract, KnownType(typeof(Building))]
abstract class Node {
    [DataMember]
    public int Foo {get;set;}
}
[DataContract]
class Building : Node {
    [DataMember]
    public string Bar {get;set;}
}

static class Program
{
    static void Main()
    {
        Dictionary<Guid, Node> data = new Dictionary<Guid, Node>();
        Type type = typeof(Dictionary<Guid, Node>);
        data.Add(Guid.NewGuid(), new Building { Foo = 1, Bar = "a" });
        StringWriter sw = new StringWriter();
        using (XmlWriter xw = XmlWriter.Create(sw))
        {
            DataContractSerializer dcs = new DataContractSerializer(type);
            dcs.WriteObject(xw, data);
        }

        string xml = sw.ToString();

        StringReader sr = new StringReader(xml);
        using (XmlReader xr = XmlReader.Create(sr))
        {
            DataContractSerializer dcs = new DataContractSerializer(type);
            Dictionary<Guid, Node> clone = (Dictionary<Guid, Node>)
                dcs.ReadObject(xr);
            foreach (KeyValuePair<Guid, Node> pair in clone)
            {
                Console.WriteLine(pair.Key + ": " + pair.Value.Foo + "/" +
                    ((Building)pair.Value).Bar);
            }
        }
    }
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...