So, My code is only 4 lines. I am trying to connect to a website, what I am trying to do after that is irrelevant because the error arised without the other codes.
import urllib.request
from bs4 import BeautifulSoup
html=urllib.request.urlopen('http://python-data.dr-chuck.net/known_by_Fikret.html').read()
soup=BeautifulSoup(html,'html.parser')
and the error(succinctly summarized one):
for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11002] getaddrinfo failed
During handling of the above exception, another exception occurred:
urllib.error.URLError: <urlopen error [Errno 11002] getaddrinfo failed>
Here is what I have tried.
- I searched for the Error returned "urlopen error [Errno 11002]” on google and especially on stackoverflow, nothing helpful was returned(In fact there are not much question on this error 11002 was asked).
- So Then I try to replace the website argument(i.e. "http://python-data.dr-chuck.net/known_by_Fikret.html" ) inside the urlopen function with another website "http://www.pythonlearn.com/code/urllinks.py". And it worked just fine. No error comes up.
- So I guess this error must have something to do with this particular website per se. The website is somewhat dynamic, by which I mean its content will alter and change into another wholly different thing. But I have no more knowledge than just to descibe what I saw.
and the longer and full version of error:
Traceback (most recent call last):
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32liburllib
equest.py", line 1240, in do_open
h.request(req.get_method(), req.selector, req.data, headers)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libhttpclient.py", line 1083, in request
self._send_request(method, url, body, headers)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libhttpclient.py", line 1128, in _send_request
self.endheaders(body)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libhttpclient.py", line 1079, in endheaders
self._send_output(message_body)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libhttpclient.py", line 911, in _send_output
self.send(msg)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libhttpclient.py", line 854, in send
self.connect()
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libhttpclient.py", line 826, in connect
(self.host,self.port), self.timeout, self.source_address)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libsocket.py", line 693, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32libsocket.py", line 732, in getaddrinfo
for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11002] getaddrinfo failed
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "D:/baiduyundownload/Tempo/Active/Python/Python Examples/Fileanalysis11111.py", line 4, in <module>
html=urllib.request.urlopen('http://python-data.dr-chuck.net/known_by_Fikret.html').read()
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32liburllib
equest.py", line 162, in urlopen
return opener.open(url, data, timeout)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32liburllib
equest.py", line 465, in open
response = self._open(req, data)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32liburllib
equest.py", line 483, in _open
'_open', req)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32liburllib
equest.py", line 443, in _call_chain
result = func(*args)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32liburllib
equest.py", line 1268, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "C:UsersAdministratorAppDataLocalProgramsPythonPython35-32liburllib
equest.py", line 1242, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [Errno 11002] getaddrinfo failed>
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