Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
958 views
in Technique[技术] by (71.8m points)

matplotlib - Python PieChart (is it possible to do CallOut labels)

Is there any examples of doing CallOut Labels with Python, Matplotlib etc

enter image description here
Image source

Something like above with a line and the label pointing from outside the pie chart.. cannot see any possible examples of it being done with Mathplotlib.... can this be done with Python??

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You may use matplotlib annotations to create text labels and annotation lines.

Manual labeling

Here is an example, where the labels are positionned manually in Data coordinates, i.e. the center of the pie is (0,0) coordinate.

import matplotlib.pyplot as plt 

fig, ax= plt.subplots(figsize=(4,4))
plt.subplots_adjust(bottom=0.3)
total = [13,87]
plt.title('How to spot intellectuals on TV')
plt.gca().axis("equal")
pie = plt.pie(total, startangle=93)
labels = ["1. They say sophisticated things", "2. They sit in front of a bookshelf"]

bbox_props = dict(boxstyle="square,pad=0.3", fc="w", ec="k", lw=0.72)
arrowprops=dict(arrowstyle="-",connectionstyle="angle,angleA=0,angleB=90")
kw = dict(xycoords='data',textcoords='data',
          arrowprops=arrowprops, bbox=bbox_props, zorder=0)
plt.gca().annotate("2", xy=(0, 0), xytext=( 1.1, -0.8), **kw )
plt.gca().annotate("1", xy=(0, 0), xytext=(-1.1,  0.8), **kw )

plt.legend(pie[0],labels, loc="center", bbox_to_anchor=(0.5,-0.1))
plt.show()

enter image description here

Automatic labeling:

We can use the angles of the wedges to automatically create labels at the positions, which are suitable.

import matplotlib.pyplot as plt
import numpy as np 

fig, ax= plt.subplots(figsize=(4,4))
plt.subplots_adjust(bottom=0.3)
total = [12,15,12,13,16]
plt.title('My repair strategies')
plt.gca().axis("equal")
patches, texts = pie = plt.pie(total, startangle=5)
labels = ["1. roaring at it", 
          "2. hitting it",
          "3. using superglue",
          "4. using duct tape",
          "5. dismantling it, then ditch it"]

bbox_props = dict(boxstyle="square,pad=0.3", fc="w", ec="k", lw=0.72)
arrowprops=dict(arrowstyle="-",connectionstyle="angle,angleA=0,angleB=90")
kw = dict(xycoords='data',textcoords='data',arrowprops=arrowprops, 
          bbox=bbox_props, zorder=0, va="center")

for i, p in enumerate(patches):
    ang = (p.theta2 - p.theta1)/2.+p.theta1
    y = np.sin(ang/180.*np.pi)
    x = 1.35*np.sign(np.cos(ang/180.*np.pi))
    plt.gca().annotate(str(1+i), xy=(0, 0), xytext=( x, y), **kw )

plt.legend(pie[0],labels, loc="center", bbox_to_anchor=(0.5,-0.2))
plt.show()

enter image description here


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...