Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
893 views
in Technique[技术] by (71.8m points)

.net - c# float [] average loses accuracy

I am trying to calculate average for an array of floats. I need to use indices because this is inside a binary search so the top and bottom will move. (Big picture we are trying to optimize a half range estimation so we don't have to re-create the array each pass).

Anyway I wrote a custom average loop and I'm getting 2 places less accuracy than the c# Average() method

float test = input.Average();

int count = (top - bottom) + 1;//number of elements in this iteration
int pos = bottom;
float average = 0f;//working average
while (pos <= top)
{
     average += input[pos];
     pos++;
}
average = average / count;

example:

0.0371166766 - c#
0.03711666 - my loop

125090.148 - c#
125090.281 - my loop 

http://pastebin.com/qRE3VrCt

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I'm getting 2 places less accuracy than the c# Average()

No, you are only losing 1 significant digit. The float type can only store 7 significant digits, the rest are just random noise. Inevitably in a calculation like this, you can accumulate round-off error and thus lose precision. Getting the round-off errors to balance out requires luck.

The only way to avoid it is to use a floating point type that has more precision to accumulate the result. Not an issue, you have double available. Which is why the Linq Average method looks like this:

   public static float Average(this IEnumerable<float> source) {
       if (source == null) throw Error.ArgumentNull("source");
       double sum = 0;         // <=== NOTE: double
       long count = 0;
       checked {
           foreach (float v in source) {
               sum += v;
               count++;
           }
       }
       if (count > 0) return (float)(sum / count);
       throw Error.NoElements();
   }

Use double to reproduce the Linq result with a comparable number of significant digits in the result.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...