That's not possible with the SQL COPY
command. COPY
only copies from a file or STDIN.
You can either write the content of the variable to a file or pipe it via STDIN. Only makes sense for more than a couple of rows.
I think I misunderstood your question before the update, you probably don't need this:
The file path can not be exchanged like other data items, and you can't use a prepared statement for that. Build the whole statement before executing or resort to dynamic SQL with a server-side function like:
CREATE OR REPLACE FUNCTION f_cp(_file text)
RETURNS void AS
$BODY$
BEGIN
EXECUTE format($$COPY zip_codes FROM %L DELIMITER ',' CSV$$, $1);
END
$BODY$
LANGUAGE plpgsql;
Call:
SELECT f_cp('/var/lib/postgres/sync/myfile.csv')
format()
requires Postgres 9.1 or later.
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