I'm trying to get class rooms with overlap course schedule, my tables: courses:
COURSE_ID NAME
11 matematika
22 logika
33 himiya
44 sport
55 algoritmika
66 hedva
77 algebra linearit
schedule:
ID COURSE_ID ID_ROOM DAY HOUR
1 11 105 Mon 10am
2 11 105 Wen 10am
3 11 105 Thu 10am
4 22 105 Mon 10am
5 22 205 Wen 10am
6 22 105 Thu 10am
7 33 305 Mon 11am
8 33 105 Mon 10am
class_room:
ID_ROOM LOCATION CAPACITY
105 A 20
205 B 10
305 C 30
My sql is:
select class_room.ID_ROOM as crid, class_room.LOCATION, schedule.DAY as d, schedule.HOUR as h, count(courses.COURSE_ID) as count
from schedule
natural join class_room
natural join courses
group by crid, d, h
order by count desc;
and I get:
crid LOCATION d h count
105 A Mon 10am 3
105 A Thu 10am 2
305 C Mon 11am 1
105 A Wen 10am 1
205 B Wen 10am 1
But I need to show all maximal values of count only (1 such row for now).
I tryed
select class_room.ID_ROOM as crid, class_room.LOCATION, schedule.DAY as d, schedule.HOUR as h, count(courses.COURSE_ID) as count
from schedule
natural join class_room
natural join courses
group by crid, d, h
having max(count)
order by count desc;
But is return empty table.
What is wrong? Or, maybe suggestion of another solution, to get what I need?
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…