There's two different possibilities here, and I'm not sure which you want, but they're both trivial to implement. You can invert (reverse may be a better word) the hue rainbow, which you can just do by using 180 - hue
. Or you can shift the color by 180 degrees by using (hue + 90) % 180
like you mention.
Reversing the colors:
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
h, s, v = cv2.split(hsv)
rev_h = 180 - h
rev_hsv = cv2.merge([rev_h, s, v])
rev_img = cv2.cvtColor(rev_hsv, cv2.COLOR_HSV2BGR)
Shifting the colors:
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
h, s, v = cv2.split(hsv)
shift_h = (h + 90) % 180
shift_hsv = cv2.merge([shift_h, s, v])
shift_img = cv2.cvtColor(shift_hsv, cv2.COLOR_HSV2BGR)
Those are the idiomatic ways to do it in OpenCV.
Now you want to do the same thing as above but only for some masked subset of pixels that meet a condition. This is not too hard to do; if you want to shift some masked pixels:
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
h, s, v = cv2.split(hsv)
h_mask = (h < 75) | (h > 128)
h[h_mask] = (h[h_mask] + 90) % 180
shift_hsv = cv2.merge([h, s, v])
shift_img = cv2.cvtColor(shift_hsv, cv2.COLOR_HSV2BGR)
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