First of all, it sounds like you want to do this:
Given a list of (name, score) tuples, return a list of names
from highest score to lowest score.
Is that right? I'm going to assume that is the questions.
Rather than go in to your code (which, when I run it, only returns ONE of the (name, score) pairs, I'll show you how I'd do it.
First in separate steps:
recommendations = [
('Gloria Pritchett', 2),
('Manny Delgado', 1),
('Cameron Tucker', 1),
('Luke Dunphy', 3)]
rec2 = [(age, name) for name, age in recommendations]
print rec2
rec3 = sorted(rec2, reverse=True)
print rec3
rec4 = [name for age, name in rec3]
print rec4
This will print:
[(2, 'Gloria Pritchett'), (1, 'Manny Delgado'), (1, 'Cameron Tucker'), (3, 'Luke Dunphy')]
[(3, 'Luke Dunphy'), (2, 'Gloria Pritchett'), (1, 'Manny Delgado'), (1, 'Cameron Tucker')]
['Luke Dunphy', 'Gloria Pritchett', 'Manny Delgado', 'Cameron Tucker']
Is that what you are looking for? In my case, "Manny" got sorted before "Cameron" (unlike your intended answer), but if they got the same score, I'm hoping that doesn't matter to you. (If it does, please clarify your question)
Old timers like me might call this a variant of the Schwartzian transform. (I guess my roots in Perl are showing...)
Anyway, here's how it works:
rec2 is a "list comprehension" with score and name swapped.
rec3 uses the built-in feature of Python to sort tuples, but with reversed=True to get high-to-low sorting.
rec4 is another "list comprehension" to drop the score and return the name.
If you must, you may put it all together in a single statement:
class_rank = [name for age, name in sorted([(age, name) for name, age in recommendations], reverse=True)]
print class_rank
You are welcome to turn this in to a function, if you'd like.
Cheers!
