Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
455 views
in Technique[技术] by (71.8m points)

python - how to parse a string into a dictionary

I am trying to parse a string to separate the lists within the string. I currently have the string:

string = "[['q1', '0', 'q1'], ['q1', '1', 'q2'], ['q2', '0', 'q2'], ['q2', '1', 'q1']]"

Is there any way to parse string so that the dictionary key is the first element of the list and the value of the key is the next to elements. For example:

{'q1': ('0','q1'), 'q1': ('1','q2'), 'q2': ('0','q2'), 'q2': ('1', 'q1')}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Insted of dictionary you can have list:
you can use ast.literal_eval to parse python data structure from string

>>> import ast
>>> my_string = "[['q1', '0', 'q1'], ['q1', '1', 'q2'], ['q2', '0', 'q2'], ['q2', '1', 'q1']]"
>>> k = ast.literal_eval(my_string)
>>> k
[['q1', '0', 'q1'], ['q1', '1', 'q2'], ['q2', '0', 'q2'], ['q2', '1', 'q1']]
>>> [[x[0],tuple(x[1:])] for x in k]
[['q1', ('0', 'q1')], ['q1', ('1', 'q2')], ['q2', ('0', 'q2')], ['q2', ('1', 'q1')]]

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...