zip(*var)
will automatically unpack your list of lists.
So, for example:
var = [['x1' ,'x2' ,'x3'], ['y1', 'y2', 'y3'], ['z1', 'z2', 'z3'], ['w1', 'w2', 'w3']]
for ltrs in zip(*var):
print(", ".join(ltrs))
results in
x1, y1, z1, w1
x2, y2, z2, w2
x3, y3, z3, w3
Edit: per comments below, he wants to use the items from a dictionary,
var = {
'id_172': ['x1', 'x2', 'x3'],
'id_182': ['y1', 'y2', 'y3'],
'id_197': ['z1', 'z2', 'z3']
}
I assume we are using the values with the keys in sorted order:
keys = sorted(var.keys())
for ltrs in zip(*(var[k] for k in keys)):
print(", ".join(ltrs))
which gives
x1, y1, z1
x2, y2, z2
x3, y3, z3
Warning: do note that this sorts the keys in lexocographic order (ie string alphabetical order), so for example "id_93" comes after "id_101". If your labels need to be sorted in numeric order you will need to use a custom key function, something like
keys = sorted(var.keys(), key=lambda k: int(k[3:]))