Lee does a good job explaining IConnectableObservable
, but Publish
isn't explained that well. It's a pretty simple animal, just hard to explain. I'll assume you understand IConnectableObservable
:
If we to re-implement the zero-param Publish
function simply and lazily, it would look something like this:
// For illustrative purposes only: don't use this code
public class PublishObservable<T> : IConnectableObservable<T>
{
private readonly IObservable<T> _source;
private readonly Subject<T> _proxy = new Subject<T>();
private IDisposable _connection;
public PublishObservable(IObservable<T> source)
{
_source = source;
}
public IDisposable Connect()
{
if(_connection == null)
_connection = _source.Subscribe(_proxy);
var disposable = Disposable.Create(() =>
{
_connection.Dispose();
_connection = null;
});
return _connection;
}
public IDisposable Subscribe(IObserver<T> observer)
{
var _subscription = _proxy.Subscribe(observer);
return _subscription;
}
}
public static class X
{
public static IConnectableObservable<T> Publish<T>(this IObservable<T> source)
{
return new PublishObservable<T>(source);
}
}
Publish
creates a single proxy Subject
which subscribes to the source observable. The proxy can subscribe/unsubscribe to source based on the connection: Call Connect
, and proxy subscribes to source. Call Dispose
on the connection disposable and the proxy unsubscribes from source. The important think to take-away from this is that there is a single Subject
that proxies any connection to the source. You're not guaranteed only one subscription to source, but you are guaranteed one proxy and one concurrent connection. You can have multiple subscriptions via connecting/disconnecting.
RefCount
handles the calling Connect
part of things: Here's a simple re-implementation:
// For illustrative purposes only: don't use this code
public class RefCountObservable<T> : IObservable<T>
{
private readonly IConnectableObservable<T> _source;
private IDisposable _connection;
private int _refCount = 0;
public RefCountObservable(IConnectableObservable<T> source)
{
_source = source;
}
public IDisposable Subscribe(IObserver<T> observer)
{
var subscription = _source.Subscribe(observer);
var disposable = Disposable.Create(() =>
{
subscription.Dispose();
DecrementCount();
});
if(++_refCount == 1)
_connection = _source.Connect();
return disposable;
}
private void DecrementCount()
{
if(--_refCount == 0)
_connection.Dispose();
}
}
public static class X
{
public static IObservable<T> RefCount<T>(this IConnectableObservable<T> source)
{
return new RefCountObservable<T>(source);
}
}
A bit more code, but still pretty simple: Call Connect
on the ConnectableObservable
if refcount goes up to 1, disconnect if it goes down to 0.
Put the two together, and you get a pair that guarantee that there will only be one concurrent subscription to a source observable, proxied through one persistent Subject
. The Subject
will only be subscribed to the source while there is >0 downstream subscriptions.
Given that introduction, there's a lot of misconceptions in your question, so I'll go over them one by one:
... Publish().RefCount() can be indeed inconsistent. Subscribing a second
time to a published sequence can cause a new subscription to the
source sequence, or not, depending on whether the source sequence was
completed while connected. If it was completed, then it won't be
resubscribed. If it was not completed, then it will be resubscribed.
.Publish().RefCount()
will subscribe anew to source under one condition only: When it goes from zero subscribers to 1. If the count of subscribers goes from 0 to 1 to 0 to 1 for any reason then you will end up re-subscribing. The source observable completing will cause RefCount
to issue an OnCompleted
, and all of its observers unsubscribe. So subsequent subscriptions to RefCount
will trigger an attempt to resubscribe to source. Naturally if source is observing the observable contract properly it will issue an OnCompleted
immediately and that will be that.
[see sample observable with OnCompleted...] The observable is subscribed twice. The
expected behavior would be that each subscription will receive one
value.
No. The expected behavior is that the proxy Subject
after issuing an OnCompleted
will re-emit an OnCompleted
to any subsequent subscription attempt. Since your source observable completes synchronously at the end of your first subscription, the second subscription will be attempting to subscribe to a Subject
that has already issued an OnCompleted
. This should result in an OnCompleted
, otherwise the Observable contract would be broken.
[see sample observable without OnCompleted as second case...] In the
first case the cold producer (the part before the
Publish().RefCount()) was subscribed only once. The first consumer
received the emitted value, but the second consumer received nothing
(except from an OnCompleted notification). In the second case the
producer was subscribed twice. Each time it generated a value, and
each consumer got one value.
This is correct. Since the proxy Subject
never completed, subsequent re-subscriptions to source will result in the cold observable re-running.
My question is: how can we fix this? [..]
- The published sequence should propagate to its subscribers all notifications coming directly from the source sequence, and nothing
else.
- The published sequence should subscribe to the source sequence when its current number of subscribers increases from zero to one.
- The published sequence should stay connected to the source as long as it has at least one subscriber.
- The published sequence should unsubscribe from the source when its current number of subscribers become zero.
All of the above currently happens with .Publish
and .RefCount
currently as long as you don't complete/error. I don't suggest implementing an operator that changes that, breaking the Observable contract.
EDIT:
I would argue the #1 source of confusion with Rx is Hot/Cold observables. Since Publish
can 'warm-up' cold observables, it's no surprise that it should lead to confusing edge cases.
First, a word on the observable contract. The Observable contract stated more succinctly is that an OnNext
can never follow an OnCompleted
/OnError
, and there should be only one OnCompleted
or OnError
notification. This does leave the edge case of attempts to subscribe to terminated observables:
Attempts to subscribe to terminated observables result in receiving the termination message immediately. Does this break the contract? Perhaps, but it's the only contract cheat, to my knowledge, in the library. The alternative is a subscription to dead air. That doesn't help anybody.
How does this tie into hot/cold observables? Unfortunately, confusingly. A subscription to an ice-cold observable triggers a re-construction of the entire observable pipeline. This means that subscribe-to-already-terminated rule only applies to hot observables. Cold observables always start anew.
Consider this code, where o
is a cold observable.:
var o = Observable.Interval(TimeSpan.FromMilliseconds(100))
.Take(5);
var s1 = o.Subscribe(i => Console.WriteLine(i.ToString()));
await Task.Delay(TimeSpan.FromMilliseconds(600));
var s2 = o.Subscribe(i => Console.WriteLine(i.ToString()));
For the purposes of the contract, the observable behind s1
and observable behind s2
are entirely different. So even though there's a delay between them, and you'll end up seeing OnNext
after OnCompleted
, that's not a problem, because they are entirely different observables.
Where it get's sticky is with a warmed-up Publish
version. If you were to add .Publish().RefCount()
to the end of o
in the code above...
- Without changing anything else,
s2
would terminate immediately printing nothing.
- Change the delay to 400 or so, and
s2
would print the last two numbers.
- Change
s1
to only .Take(2)
, and s2
would start over again printing 0 through 4.
Making this nastiness worse, is the Shroedinger's cat effect: If you set up an observer on o
to watch what would happen the whole time, that changes the ref-count, affecting the functionality! Watching it, changes the behavior. Debugging nightmare.
This is the hazard of attempting to 'warm-up' cold observables. It just doesn't work well, especially with Publish/RefCount
.
My advice would be:
- Don't try to warm up cold observables.
- If you need to share a subscription, with either cold or hot observables, stick with @Enigmativity's general rule of strictly using the selector
Publish
version
- If you must, have a dummy subscription on a
Publish/RefCount
observable. This at least provides a consistent Refcount >= 1, reducing the quantum activity effect.