The code below is streaming the twitter public timeline for a variable which output any tweets to the console. I'd like the save the same variables (status.text, status.author.screen_name, status.created_at, status.source) into an sqlite database. I'm getting an syntax error when my script sees a tweet and nothing is written to the sqlite database.
the error:
$ python stream-v5.py @lunchboxhq
Filtering the public timeline for "@lunchboxhq"RT @LunchboxHQ: test 2 LunchboxHQ 2012-02-29 18:03:42 Echofon
Encountered Exception: near "?": syntax error
the code:
import sys
import tweepy
import webbrowser
import sqlite3 as lite
# Query terms
Q = sys.argv[1:]
sqlite3file='/var/www/twitter.lbox.com/html/stream5_log.sqlite'
CONSUMER_KEY = ''
CONSUMER_SECRET = ''
ACCESS_TOKEN = ''
ACCESS_TOKEN_SECRET = ''
auth = tweepy.OAuthHandler(CONSUMER_KEY, CONSUMER_SECRET)
auth.set_access_token(ACCESS_TOKEN, ACCESS_TOKEN_SECRET)
con = lite.connect(sqlite3file)
cur = con.cursor()
cur.execute("CREATE TABLE TWEETS(txt text, author text, created int, source text)")
class CustomStreamListener(tweepy.StreamListener):
def on_status(self, status):
try:
print "%s%s%s%s" % (status.text,
status.author.screen_name,
status.created_at,
status.source,)
cur.executemany("INSERT INTO TWEETS(?, ?, ?)", (status.text,
status.author.screen_name,
status.created_at,
status.source))
except Exception, e:
print >> sys.stderr, 'Encountered Exception:', e
pass
def on_error(self, status_code):
print >> sys.stderr, 'Encountered error with status code:', status_code
return True # Don't kill the stream
def on_timeout(self):
print >> sys.stderr, 'Timeout...'
return True # Don't kill the stream
streaming_api = tweepy.streaming.Stream(auth, CustomStreamListener(), timeout=60)
print >> sys.stderr, 'Filtering the public timeline for "%s"' % (' '.join(sys.argv[1:]),)
streaming_api.filter(follow=None, track=Q)
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