Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
674 views
in Technique[技术] by (71.8m points)

javascript - using await inline on variable in outer scope

(async function iife () {
  const numbers = [1, 2, 3, 4]
  let count = 0
  async function returnNumberAsync (number) {
    return new Promise(resolve => {
      setTimeout(() => resolve(number), 0)
    })
  }
  await Promise.all(numbers.map(async number => {
    count += await returnNumberAsync(number)
  }))
  console.log(count)
})()

This snippet logs 4 to the console, which is completely beyond me. As soon as I assign the promised value inside map to its own local variable …

const result = await returnNumberAsync(number)
count += result;

… it logs 10 like I'd expect. What's happening when I count += await …??

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

When you do count += await <expression>, the initial value of count to be added to the resolve value is saved before the await part is resolved. So

count += await returnNumberAsync(number)

is like

count = count + await returnNumberAsync(number)

as you can see:

(async function iife () {
  const numbers = [1, 2, 3, 4]
  let count = 0
  async function returnNumberAsync (number) {
    return new Promise(resolve => {
      setTimeout(() => resolve(number), 0)
    })
  }
  await Promise.all(numbers.map(async number => {
    count = count + await returnNumberAsync(number)
  }))
  console.log(count)
})()

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...