how to parse a string in Shell script

Question

I want to parse the following string in shell script.

VERSION=2.6.32.54-0.11.def

Here I want to get two value.

first = 263254
second = 11

I am using following to get the first value:

first=`expr substr $VERSION 1 9| sed "s/.//g" |sed "s/-//g"`

to get the second:

second=`expr substr $VERSION 10 6| sed "s/.//g" |sed "s/-//g"`

Using above code the output is:

first=263254
second=11

The result wont be consistent if version is changed to:

VERSION=2.6.32.54-0.1.def

Here second value will become 1d, but I want it give output of 1 only.

How can I directly parse the number after '-' and before '.d'?

Answer 1

$ first=$(echo $VERSION | cut -d- -f1 | sed 's/.//g')
$ second=$(echo $VERSION | cut -d- -f2 | cut -d. -f2)