Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
2.0k views
in Technique[技术] by (71.8m points)

haskell - Getting the data constructor name as a string using GHC.Generics

I'd like something like the following:

constrName :: Data a=> a -> String
constrName = showConstr . toConstr

But for GHC.Generics. I see the Constructor class, but don't see any instances in scope. I'm using base-4.8.1.0.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Adapting this gist by Nathan Howell: https://gist.github.com/NathanHowell/6201625 :

{-# LANGUAGE DeriveGeneric #-}
{-# LANGUAGE FlexibleInstances #-}
{-# LANGUAGE KindSignatures #-}
{-# LANGUAGE TypeSynonymInstances #-}
{-# LANGUAGE TypeOperators #-}
{-# LANGUAGE FlexibleContexts #-}

import GHC.Generics

constrName :: (HasConstructor (Rep a), Generic a)=> a -> String
constrName = genericConstrName . from 

class HasConstructor (f :: * -> *) where
  genericConstrName :: f x -> String

instance HasConstructor f => HasConstructor (D1 c f) where
  genericConstrName (M1 x) = genericConstrName x

instance (HasConstructor x, HasConstructor y) => HasConstructor (x :+: y) where
  genericConstrName (L1 l) = genericConstrName l
  genericConstrName (R1 r) = genericConstrName r

instance Constructor c => HasConstructor (C1 c f) where
  genericConstrName x = conName x

--------------
data Foo = Bar Int | Baz Float deriving Generic
newtype X = X Char deriving Generic
data Y = Y deriving Generic

We can do:

*Main> constrName (Bar 1)
"Bar"
*Main> constrName $ X 'a'
"X"
*Main> constrName Y
"Y"

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...