Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
851 views
in Technique[技术] by (71.8m points)

javascript - Show box or input box on checked box

how can I make this work...

If I select a box it shows my input box or whatever I need to show when a box is checked ... the problem is that I have 5 check box...

so If the user select

Box 1 [x]
Box 2 [x]
Box 3 [x]
box 4 [x]
Box 5 [ ]

up to this point the code works fine... but then he/she realize that no longer want the Box 3 and want to switch 3 for 5 ... before clic the submit button

Box 1 [x]
Box 2 [x]
Box 3 [ ]
box 4 [x]
Box 5 [x]

When that happen the input box change from show to hide... and I don't want that since 1,2,4 and 5 still selected ...

If there where no one selected then sure show nothing... but as long as there is one selected then the input box or button or text or whatever is needed must be shown...

Here is the code for testing:

The HTML

  <input type="checkbox" name="supplied" id="supplied" value="supplied" class="aboveage2" />
  <input type="checkbox" name="supplied" id="supplied_1" value="supplied" class="aboveage2" />
  <input type="checkbox" name="supplied" id="supplied_2" value="supplied" class="aboveage2" />
  <input type="checkbox" name="supplied" id="supplied_3" value="supplied" class="aboveage2" />
  <input type="checkbox" name="supplied" id="supplied_4" value="supplied" class="aboveage2" />
  <input type="checkbox" name="supplied" id="supplied_5" value="supplied" class="aboveage2" />

<ul id="date" style="display:none">
    <li><input id="start" name="start" size="5" type="text" class="small" value="1" /></li>
    <li><input id="end" name="end" size="5" type="text" class="small" value="2" /></li>
</ul>

The Java

  $('#supplied, #supplied_1, #supplied_2, #supplied_3, #supplied_4, #supplied_5').live('change', function(){
      if ( $(this).is(':checked') ) {
         $('#date').show();
     } else {
         $('#date').hide();
     }
 });

The link to live test: http://jsfiddle.net/GBSZ8/284/

Thank you.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
$('.aboveage2').live('change', function() {

    if ( $(".aboveage2:checked").length > 0 ) {
        $('#date').show();
    } else {
        $('#date').hide();
    }
});

Demo: http://jsfiddle.net/samliew/GBSZ8/295/

Note that live works only for jQuery 1.7 or lower. For migration to latest jQuery, see jQuery 1.9 .live() is not a function


UPDATE:

Your checkbox class on your website is different from the one in the question!!!

Use this selector instead:

$('input[name*=accessory_id]').live('change', function() {

    if ( $("input[name*=accessory_id]:checked").length > 0 ) {
        $('#date').show();
    } else {
        $('#date').hide();
    }
});

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...