I have a php page generating and displaying a table. for the last row in the table i want to display an image with an 'onclick' function attached. this will send the username for the selected row to a script that will use AJAX to update a database. The table displays fine but the AJAX is not working. my php to display the image is:
echo "<td> <img id='tblimg'
onclick='like('" . $row['Username'] . "')'
src='like.jpg' alt='like/dislike image'
width='80px' height='30px'></td>";
The javascript function is:
<script type="text/javascript" >
function like(user)
{
$.ajax(
url: "update.php",
type: "POST",
data: { 'username': user, 'liked': '1' },
success: function()
{
alert("ok");
}
);
}
</script>
And here is update.php:
<?php
$con=mysqli_connect("","sam74","********","sam74");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$Username = $_POST['username'];
$Liked = $_POST['liked'];
$sql = "UPDATE 'followers' SET 'Liked' = '$Liked' WHERE 'Username' = '$Username'";
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
mysqli_close($con);
?>
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…