I need help with the capture logic for my Android Application.
(我需要有关Android应用程序捕获逻辑的帮助。)
I have implemented movement where the pieces only move diagonally.
(我实现了运动,其中棋子只沿对角线移动。)
So, now I need help so that I would be able to implement the capture logic for checkers game. (因此,现在我需要帮助,以便能够实现跳棋游戏的捕获逻辑。)
Here is my code I used move movement and to move diagonally:
(这是我使用移动动作并沿对角线移动的代码:)
private boolean handleDownAction(MotionEvent event) {
// determine what kind of touch event we have
if (event.getActionMasked() == MotionEvent.ACTION_DOWN && touch == false) {
theX = (int) (event.getX() / WidthBoard);
theY = (int) (event.getY() / HeightBoard);
touch = true;
invalidate();
return true;
}
// determine what kind of touch event we have
if (event.getActionMasked() == MotionEvent.ACTION_DOWN && touch == true) {
if(player2 == true) {
if(coins[theY][theX] == 2) {
axixX = (int) (event.getX() / WidthBoard);
axixY = (int) (event.getY() / HeightBoard);
if(axixY == theY - 1 && axixX == theX + 1 ){
//if( pieces[end_y][end_x] == 1){
coins[axixY][axixX] = coins[theY][theX];
Toast.makeText(getContext(), "Player 2 Your Turn", Toast.LENGTH_LONG).show();
coins[theY][theX] = 0;
player1 = true;
player2 = false;
//}
touch = false;
invalidate();
}
else {
Toast.makeText(getContext(), "Illegal Move Can Only Move Diagonaly", Toast.LENGTH_LONG).show();
}
System.out.println("ACTION DOWN Y " + axixY+ " End x " + axixX );
System.out.println("Start X " + theY + " Start Y " + theX);
// touch = false;
// playerPieces(event,start_y,start_x);
}
}
else if( coins[theY][theX] == 1){
axixX = (int) (event.getX() / WidthBoard);
axixY = (int) (event.getY() / HeightBoard);
System.out.println("ACTION DOWN AC " + axixY + " " + axixX);
if(axixY == theY+1 && axixX == theX -1 ){
Toast.makeText(getContext(), "Player 1 Your Turn", Toast.LENGTH_LONG).show();
coins[axixY][axixX]= coins[theY][theX] ;
coins[theY][theX]= 0;
player1=false;
player2=true;
touch = false;
invalidate();
}
// invalidate();
}
touch =false;
return true;
}
System.out.println( x + " " + y);
return true;
}
Please help me to resolve this issue.
(请帮助我解决此问题。)
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