javascript - 将JavaScript函数作为参数传递(Pass a JavaScript function as parameter)

Question

How do I pass a function as a parameter without the function executing in the "parent" function or using eval() ?(如何在没有“父”函数中执行的函数或使用eval()情况下将函数作为参数传递？)

(Since I've read that it's insecure.)(（因为我读过它是不安全的。）) I have this:(我有这个：) addContact(entityId, refreshContactList()); It works, but the problem is that refreshContactList fires when the function is called, rather than when it's used in the function.(它可以工作，但问题是refreshContactList在调用函数时触发，而不是在函数中使用它时触发。) I could get around it using eval() , but it's not the best practice, according to what I've read.(我可以使用eval()绕过它，但根据我所读到的，这不是最好的做法。) How can I pass a function as a parameter in JavaScript?(如何在JavaScript中将函数作为参数传递？)   ask by imperium2335 translate from so

Answer 1

You just need to remove the parenthesis:(您只需要删除括号：)

addContact(entityId, refreshContactList); This then passes the function without executing it first.(然后，它会先传递函数而不先执行它。) Here is an example:(这是一个例子：) function addContact(id, refreshCallback) { refreshCallback(); // You can also pass arguments if you need to // refreshCallback(id); } function refreshContactList() { alert('Hello World'); } addContact(1, refreshContactList);