javascript - 从数组中存在的所有子数组中获取所有元素，而不从主体数组中删除元素？ [重复](Get all elements from all subarrays present in an array without removing element from the principal array? [duplicate])

Question

This question already has answers here) : 这个问题已经在这里有了答案) ：)

Merge/flatten an array of arrays (74 answers) 合并/展平数组 （74个答案）)

Transform Javascript subArrays into one Array [duplicate] (4 answers) 将Javascript子数组转换为一个数组[重复] （4个答案）)

Closed 7 mins ago . 7分钟前关闭。)

I work on a project with a lot of arrays and in some case I have this:

(我在一个有很多数组的项目上工作，在某些情况下，我有这个问题：)

let main_array = [a,b,c,d,[e,f,g],h,i,j,[k,l,m,o],[p],q,[]]

In my main array I have a lot of subarrays, and I want to get all element from them without removing the other elements from the main array.

(在我的主数组中，我有很多子数组，我想从中获取所有元素，而又不从主数组中删除其他元素。)

So I want a function which can do this:

(所以我想要一个可以做到这一点的函数：)

f(main_array) --> [a,b,c,d,e,f,g,h,i,j,k,l,m,o,p,q]

The particularity with the main array is about the number of arrays inside it, in fact, it could have 0 to n subarray(s) with 0 to n element(s).

(主数组的特殊性是关于其内部数组的数量，实际上，它可以具有0到n个子数组以及0到n个元素。)

Is there an existing built-in function or just a simple function with filter for example that can solve this problem in a few line of code (just 1 could be great !) ?

(是否存在现有的内置函数或仅带有过滤器的简单函数，例如，可以在几行代码中解决此问题（仅1个就可以了！）？)

PS: I use node.js

(PS：我使用node.js)

  ask by bosskay972 translate from so

Answer 1

等待大神答复