java - 如何使用任何空白字符分隔字符串来分隔符？(How do I split a string with any whitespace chars as delimiters?)

Question

我需要哪种正则表达式模式传递给java.lang.String.split()方法，以使用所有空格字符（''，'\ t'，'\ n'等）将字符串拆分为子字符串数组作为分隔符？

  ask by mcjabberz translate from so

Answer 1

Something in the lines of

(某些东西)

myString.split("\s+");

This groups all white spaces as a delimiter.

(这会将所有空白分组为分隔符。)

So if I have the string:

(因此，如果我有字符串：)

"Hello[space][tab]World"

This should yield the strings "Hello" and "World" and omit the empty space between the [space] and the [tab] .

(这将产生字符串"Hello"和"World"并省略[space]和[tab]之间的[space] 。)

As VonC pointed out, the backslash should be escaped, because Java would first try to escape the string to a special character, and send that to be parsed.

(正如VonC指出的那样，应该转义反斜杠，因为Java首先会尝试将字符串转义为特殊字符，然后将其发送给解析。)

What you want, is the literal "\s" , which means, you need to pass "\\s" .

(您想要的是文字"\s" ，这意味着您需要传递"\\s" 。)

It can get a bit confusing.

(可能会造成一些混乱。)

The \\s is equivalent to [ \\t\\n\\x0B\\f\\r]

(\\s等效于[ \\t\\n\\x0B\\f\\r])