javascript - Iterating through an array of objects and select an object by number of occurrences in the array

Question

const bondFilms = [
  { "title" : "Skyfall", "year" : 2012, "actor" : "Daniel Craig", "gross" : "$1,108,561,008" },
  { "title" : "Thunderball", "year" : 1965, "actor" : "Sean Connery", "gross" : "$1,014,941,117" },
  { "title" : "Goldfinger", "year" : 1964, "actor" : "Sean Connery", "gross" : "$912,257,512" },
  { "title" : "Live and Let Die", "year" : 1973, "actor" : "Roger Moore", "gross" : "$825,110,761" },
  { "title" : "You Only Live Twice", "year" : 1967, "actor" : "Sean Connery", "gross" : "$756,544,419" },
  { "title" : "The Spy Who Loved Me", "year" : 1977, "actor" : "Roger Moore", "gross" : "$692,713,752" },
  { "title" : "Casino Royale", "year" : 2006, "actor" : "Daniel Craig", "gross" : "$669,789,482" },
  { "title" : "Moonraker", "year" : 1979, "actor" : "Roger Moore", "gross" : "$655,872,400" },
  { "title" : "Diamonds Are Forever", "year" : 1971, "actor" : "Sean Connery", "gross" : "$648,514,469" },
  { "title" : "Quantum of Solace", "year" : 2008, "actor" : "Daniel Craig", "gross" : "$622,246,378" },
  { "title" : "From Russia with Love", "year" : 1963, "actor" : "Sean Connery", "gross" : "$576,277,964" },
  { "title" : "Die Another Day", "year" : 2002, "actor" : "Pierce Brosnan", "gross" : "$543,639,638" },
  { "title" : "Goldeneye", "year" : 1995, "actor" : "Pierce Brosnan", "gross" : "$529,548,711" },
  { "title" : "On Her Majesty's Secret Service", "year" : 1969, "actor" : "George Lazenby", "gross" : "$505,899,782" },
  { "title" : "The World is Not Enough", "year" : 1999, "actor" : "Pierce Brosnan", "gross" : "$491,617,153" },
  { "title" : "For Your Eyes Only", "year" : 1981, "actor" : "Roger Moore", "gross" : "$486,468,881" },
  { "title" : "Tomorrow Never Dies", "year" : 1997, "actor" : "Pierce Brosnan", "gross" : "$478,946,402" },
  { "title" : "The Man with the Golden Gun", "year" : 1974, "actor" : "Roger Moore", "gross" : "$448,249,281" },
  { "title" : "Dr. No", "year" : 1962, "actor" : "Sean Connery", "gross" : "$440,759,072" },
  { "title" : "Octopussy", "year" : 1983, "actor" : "Roger Moore", "gross" : "$426,244,352" },
  { "title" : "The Living Daylights", "year" : 1987, "actor" : "Timothy Dalton", "gross" : "$381,088,866" },
  { "title" : "A View to a Kill", "year" : 1985, "actor" : "Roger Moore", "gross" : "$321,172,633" },
  { "title" : "License to Kill", "year" : 1989, "actor" : "Timothy Dalton", "gross" : "$285,157,191" }
];

const leastBondAppearance = []
for (let i = 0; i < bondFilms.length; i++){
    leastBondAppearance.push(bondFilms[i].actor)
}
// console.log(leastBondAppearance)
let findDuplicates = arr => arr.filter((item, index) => arr.indexOf(item) != index)
 console.log(findDuplicates(leastBondAppearance))

question from:https://stackoverflow.com/questions/65914469/iterating-through-an-array-of-objects-and-select-an-object-by-number-of-occurren

Answer 1

let actors = {}

bondFilms.forEach(f => {
    if (!actors[f.actor]) actors[f.actor] = 0
    actors[f.actor] = actors[f.actor]+1 // or actors[f.actor]++
    })

let sortedActorNames = Object.keys(actors).sort((a,b) => actors[a]-actors[b])

console.log(sortedActorNames[0])