Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
119 views
in Technique[技术] by (71.8m points)

Function blocked (Python)

A loop is blocking the function changeStockPrice, making variable stockA the default value (0.2). Please tell me the problem and how to fix it

I'm pretty sure changeStockPrice is the problem as:

print(get_stocklist())

This gets the default value (0.2)

print(round(abs(stockA + random.randint(-20, 20)/10),1))

This works perfectly (ranging from 0 to 2.2)

This is a simplified version of my code:

import random
import time

stockA = 0.2

def get_stocklist():
  response = f"""Stocks:
  1E Discord {stockA}
  """
  return(response)

def changeStockPrice(stock):
  stock = round(abs(stock + random.randint(-20, 20)/10),1)
  return(stock)

def stockPriceChanger():
  global stockA

  while True:
    time.sleep(5)
    stockA = changeStockPrice(stockA)

print(get_stocklist())
print(round(abs(stockA + random.randint(-20, 20)/10),1))
question from:https://stackoverflow.com/questions/65882172/function-blocked-python

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
def stockPriceChanger():
  global stockA

  while True:
    time.sleep(5)
    stockA = changeStockPrice(stockA)
    yield  #break (if you want to break it)

Here, the function goes in the infinite Loop. To avoid this situation you must break the while loop or put some condition to break it.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...