Find all matches in string with regex in any order with Javascript

Question

How can i find all matches below? The way i've got it now, it finds finds any match from the keywords array, but, since the word "not" is present, matches should be empty in the console.

var title = "How to edit an image";
var keywords = ["image","edit","not"];
var matches = [];
if (title.search(new RegExp(keywords.join("|"),"i")) != -1) {
     matches.push(title);
}
console.log(matches);

question from:https://stackoverflow.com/questions/66065352/find-all-matches-in-string-with-regex-in-any-order-with-javascript

Answer 1

No need for the regex, just loop through the words using every() , and check each keyword using includes() (See below);

console.log(Check("How to edit an image", ["image","edit","not"])); // false
console.log(Check("How to edit an image", ["image","edit"]));       // true

function Check(title, keywords) {
    return keywords.every(word => title.indexOf(word) > -1);
}