Address of the array vs. address of array[0]- Python

Question

In C++ the address of the first element in an array/list is the same as the address of array itself, in the memory. However, when I try the "ID" function in Python to investigate the addresses, I get different IDs for the array[0] and the array itself. Is using ID a correct approach to find the address of the data structure in Python? for example:

arr = [1,2,3,4]
print(id(arr))
print(id(arr[0]))

I get 17145608 for the id(arr) and 2039216048 for id(arr[0]). the ID are not even close to each other. Thanks for your time and help.

question from:https://stackoverflow.com/questions/66059368/address-of-the-array-vs-address-of-array0-python

Answer 1

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