You can put your logic to assign the picture in your randomNumber function, the best would be to rename it to something like generateRandomPicture.
Then you need an element with the id you have specified and
also I would recommend that you use an eventListener instead of doing the inline scripting.
You can add .addEventListener() to your element.
document.getElementById('b').addEventListener('click', randomNumber);
document.getElementById('b').addEventListener('click', randomNumber);
function randomNumber() {
let number = Math.floor((Math.random() * 6) + 1);
if (number == 1) {
document.getElementById('img1').src = "image/dice1.jpg";
} else if (number == 2) {
document.getElementById('img1').src = "image/dice2.jpg";
} else if (number == 3) {
document.getElementById("img1").src = "image/dice3.jpg"
} else if (number == 4) {
document.getElementById("img1").src = "image/dice4.jpg";
} else if (number == 5) {
document.getElementById("img1").src = "image/dice5.jpg";
} else if (number == 6) {
document.getElementById("img1").src = "image/dice6.jpg";
}
}
<head>
<title></title>
</head>
<body>
<p id="number"> </p>
<img id="img1"></img>
<button id="b"> Yes </button>
<button onclick="Num2button()">No</button>
</body>
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