c++ - Why does return 0 or break not work with the comma operator?

Question

I can write the code if(1) x++, y++; instead of if(1) {x++; y++;}, but in some cases it does not work (see below). It would be nice if you tell me about this.

int x = 5, y = 10;    
if (x == 5) x++, y++;  // It works

if (x == 5) x++, return 0; // It shows an error

The same applies to for loops:

for (int i = 0; i < 1; i++) y++, y += 5; // It works

for (int i = 0; i < 1; i++) y++, break; // Does not work

question from:https://stackoverflow.com/questions/51942943/why-does-return-0-or-break-not-work-with-the-comma-operator

Answer 1

That's because return and break are statements, not expressions. As such, you cannot use it in another expression in any way. if and the others are similarly also statements.

What you can do however is rewrite your expression (for return) so that it's not nested in an expression - not that I recommend writing code like that:

return x++, 0;

You can't do that for break because it doesn't accept an expression.