Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
220 views
in Technique[技术] by (71.8m points)

What does # mean in Lua?

I have seen the hash character '#' being added to the front of variables a lot in Lua.

What does it do?

EXAMPLE

-- sort AIs in currentlevel
table.sort(level.ais, function(a,b) return a.y < b.y end)
local curAIIndex = 1
local maxAIIndex = #level.ais
for i = 1,#currentLevel+maxAIIndex do
    if level.ais[curAIIndex].y+sprites.monster:getHeight() < currentLevel[i].lowerY then
        table.insert(currentLevel, i, level.ais[curAIIndex])
        curAIIndex = curAIIndex + 1
        if curAIIndex > maxAIIndex then
            break
        end
    end
end

Apologies if this has already been asked, I've searched around on the internet a lot but I haven't seem to have found an answer. Thanks in advance!

question from:https://stackoverflow.com/questions/17974622/what-does-mean-in-lua

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

That is the length operator:

The length operator is denoted by the unary operator #. The length of a string is its number of bytes (that is, the usual meaning of string length when each character is one byte).

The length of a table t is defined to be any integer index n such that t[n] is not nil and t[n+1] is nil; moreover, if t[1] is nil, n can be zero. For a regular array, with non-nil values from 1 to a given n, its length is exactly that n, the index of its last value. If the array has "holes" (that is, nil values between other non-nil values), then #t can be any of the indices that directly precedes a nil value (that is, it may consider any such nil value as the end of the array).


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...