dictionary - Is there a fast way to generate a dict of the alphabet in Python?

Question

I want to generate a dict with the letters of the alphabet as the keys, something like

letter_count = {'a': 0, 'b': 0, 'c': 0}

what would be a fast way of generating that dict, rather than me having to type it in?

Thanks for your help.

(EDIT)

Thanks everyone for your solutions :) nosklo's solution is probably the shortest Also, thanks for reminding me about the Python string module. question from:https://stackoverflow.com/questions/453576/is-there-a-fast-way-to-generate-a-dict-of-the-alphabet-in-python

Answer 1

I find this solution more elegant:

import string
d = dict.fromkeys(string.ascii_lowercase, 0)