c# - Culture invariant Decimal.TryParse()

Question

I'm writing a custom string to decimal validator that needs to use Decimal.TryParse that ignores culture (i.e. doesn't care if the input contains "." or "," as decimal point separator). This is the suggested method:

public static bool TryParse(
    string s,
    NumberStyles style,
    IFormatProvider provider,
    out decimal result
)

I can't figure out what to use as the 3rd parameter. The examples I've seen look like this:

culture = CultureInfo.CreateSpecificCulture("en-GB");
Decimal.TryParse(value, style, culture, out number)

so they create a specific culture. CultureInfo does not have a "CreateInvariantCulture" method, and CultureInfo.InvariantCulture is not of the required type. What's the correct usage?

question from:https://stackoverflow.com/questions/23131414/culture-invariant-decimal-tryparse

Answer 1

Have try like this :

decimal value;
bool b = Decimal.TryParse("0.1", NumberStyles.Any, new CultureInfo("en-US"), out value);

The best way would likely be to use the Decimal.Parse() method as you would traditionally with any decimal string values.

You can use NumberStyles.Currency to specify that the values be read in as currency, which will take care of any currency-related values (you will need to add a Reference to System.Globalalization to use this :

using System.Globalization;

Decimal.Parse also accepts a third-parameter, which will allow you to explicitly set the IFormatProvider if you so choose and wish to you a specific Culture :

decimal value = Decimal.Parse(currency, NumberStyles.Currency, CultureInfo.InvariantCulture); //yields 15.55