[input[i:i+n] for i in range(0, len(input), n)] # Use xrange in py2k
where n
is the length of a chunk.
Since you don't define what might happen to the final element of the new list when the number of elements in input
is not divisible by n
, I assumed that it's of no importance: with this you'll get last element equal 2 if n
equal 7, for example.
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…