c++ - Is it more efficient to preallocate a vector?

Question

In C++ Primer fourth edition, by Stanley B.Lippman, Josee Lajoie and Barbara E. Moo it states:

Because vectors grow efficiently, it is usually best to let the vector grow by adding elements to it dynamically as the element values are known.

and

Readers accustomed to using c or java might expect that because vector elements are stored contiguously, it would be best to preallocate the vector at its expected size. In fact the contrary is the case...

and

Allthough we can preallocate a given number of elements in a vector, it is usually more efficient to define an empty vector and add elements to it.

Assuming this is correct (the authors are as reputable as they come, one is a co-author of C++ itself) then can anyone give me a case that proves this statement, and explain why?

question from:https://stackoverflow.com/questions/11888265/is-it-more-efficient-to-preallocate-a-vector

Answer 1

It depends.

If you don't know what the final size will be, then let the vector allocate using its allocation scheme (usually doubles each time, or somewhere around there). This way you avoid reallocating for every single element:

std::vector<int> v;

// good:
for (/* populate v */) // unknown number of iterations
{
    v.push_back(i); // possible reallocation, but not often
}

// bad:
for (/* populate v */) // unknown number of iterations
{
    v.reserve(v.size() + 1); // definite reallocation, every time
    v.push_back(i); // (no reallocation)
}

But if you know ahead of time you won't be reallocating, then preallocate:

std::vector<int> v;

// good:
v.reserve(10); 
for (/* populate v */) // only 10 iterations (for example)
{
    v.push_back(i); // no reallocations
}

// not bad, but not the best:
for (/* populate v */) // only 10 iterations (for example)
{
    v.push_back(i); // possible reallocation, but not often (but more than needed!)
}