Editor's note: This code example is from a version of Rust prior to 1.0 and is not syntactically valid Rust 1.0 code. Updated versions of this code produce different errors, but the answers still contain valuable information.
I came across the following example of how to generate a random number using Rust, but it doesn't appear to work. The example doesn't show which version of Rust it applies to, so perhaps it is out-of-date, or perhaps I got something wrong.
// http://static.rust-lang.org/doc/master/std/rand/trait.Rng.html
use std::rand;
use std::rand::Rng;
fn main() {
let mut rng = rand::task_rng();
let n: uint = rng.gen_range(0u, 10);
println!("{}", n);
let m: float = rng.gen_range(-40.0, 1.3e5);
println!("{}", m);
}
When I attempt to compile this, the following error results:
test_rand002.rs:6:17: 6:39 error: type `@mut std::rand::IsaacRng` does not
implement any method in scope named `gen_range`
test_rand002.rs:6 let n: uint = rng.gen_range(0u, 10);
^~~~~~~~~~~~~~~~~~~~~~
test_rand002.rs:8:18: 8:46 error: type `@mut std::rand::IsaacRng` does not
implement any method in scope named `gen_range`
test_rand002.rs:8 let m: float = rng.gen_range(-40.0, 1.3e5);
^~~~~~~~~~~~~~~~~~~~~~~~~~~~
There is another example (as follows) on the same page (above) that does work. However, it doesn't do exactly what I want, although I could adapt it.
use std::rand;
use std::rand::Rng;
fn main() {
let mut rng = rand::task_rng();
let x: uint = rng.gen();
println!("{}", x);
println!("{:?}", rng.gen::<(f64, bool)>());
}
How can I generate a "simple" random number using Rust (e.g.: i64
) within a given range (e.g.: 0 to n)?
question from:
https://stackoverflow.com/questions/19671845/how-can-i-generate-a-random-number-within-a-range-in-rust 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…