python - Evaluate multiple scores on sklearn cross_val_score

Question

I'm trying to evaluate multiple machine learning algorithms with sklearn for a couple of metrics (accuracy, recall, precision and maybe more).

For what I understood from the documentation here and from the source code(I'm using sklearn 0.17), the cross_val_score function only receives one scorer for each execution. So for calculating multiple scores, I have to :

1. Execute multiple times

2. Implement my (time consuming and error prone) scorer

   I've executed multiple times with this code :

   from sklearn.svm import SVC
   from sklearn.naive_bayes import GaussianNB
   from sklearn.tree import DecisionTreeClassifier
   from sklearn.cross_validation import  cross_val_score
   import time
   from sklearn.datasets import  load_iris
   
   iris = load_iris()
   
   models = [GaussianNB(), DecisionTreeClassifier(), SVC()]
   names = ["Naive Bayes", "Decision Tree", "SVM"]
   for model, name in zip(models, names):
       print name
       start = time.time()
       for score in ["accuracy", "precision", "recall"]:
           print score,
           print " : ",
           print cross_val_score(model, iris.data, iris.target,scoring=score, cv=10).mean()
       print time.time() - start
   

And I get this output:

Naive Bayes
accuracy  :  0.953333333333
precision  :  0.962698412698
recall  :  0.953333333333
0.0383198261261
Decision Tree
accuracy  :  0.953333333333
precision  :  0.958888888889
recall  :  0.953333333333
0.0494720935822
SVM
accuracy  :  0.98
precision  :  0.983333333333
recall  :  0.98
0.063080072403

Which is ok, but it's slow for my own data. How can I measure all scores ?

question from:https://stackoverflow.com/questions/35876508/evaluate-multiple-scores-on-sklearn-cross-val-score

Answer 1

Since the time of writing this post scikit-learn has updated and made my answer obsolete, see the much cleaner solution below

---

You can write your own scoring function to capture all three pieces of information, however a scoring function for cross validation must only return a single number in scikit-learn (this is likely for compatibility reasons). Below is an example where each of the scores for each cross validation slice prints to the console, and the returned value is just the sum of the three metrics. If you want to return all these values, you're going to have to make some changes to cross_val_score (line 1351 of cross_validation.py) and _score (line 1601 or the same file).

from sklearn.svm import SVC
from sklearn.naive_bayes import GaussianNB
from sklearn.tree import DecisionTreeClassifier
from sklearn.cross_validation import  cross_val_score
import time
from sklearn.datasets import  load_iris
from sklearn.metrics import accuracy_score, precision_score, recall_score

iris = load_iris()

models = [GaussianNB(), DecisionTreeClassifier(), SVC()]
names = ["Naive Bayes", "Decision Tree", "SVM"]

def getScores(estimator, x, y):
    yPred = estimator.predict(x)
    return (accuracy_score(y, yPred), 
            precision_score(y, yPred, pos_label=3, average='macro'), 
            recall_score(y, yPred, pos_label=3, average='macro'))

def my_scorer(estimator, x, y):
    a, p, r = getScores(estimator, x, y)
    print a, p, r
    return a+p+r

for model, name in zip(models, names):
    print name
    start = time.time()
    m = cross_val_score(model, iris.data, iris.target,scoring=my_scorer, cv=10).mean()
    print '
Sum:',m, '

'
    print 'time', time.time() - start, '

'

Which gives:

Naive Bayes
0.933333333333 0.944444444444 0.933333333333
0.933333333333 0.944444444444 0.933333333333
1.0 1.0 1.0
0.933333333333 0.944444444444 0.933333333333
0.933333333333 0.944444444444 0.933333333333
0.933333333333 0.944444444444 0.933333333333
0.866666666667 0.904761904762 0.866666666667
1.0 1.0 1.0
1.0 1.0 1.0
1.0 1.0 1.0

Sum: 2.86936507937 


time 0.0249638557434 


Decision Tree
1.0 1.0 1.0
0.933333333333 0.944444444444 0.933333333333
1.0 1.0 1.0
0.933333333333 0.944444444444 0.933333333333
0.933333333333 0.944444444444 0.933333333333
0.866666666667 0.866666666667 0.866666666667
0.933333333333 0.944444444444 0.933333333333
0.933333333333 0.944444444444 0.933333333333
1.0 1.0 1.0
1.0 1.0 1.0

Sum: 2.86555555556 


time 0.0237860679626 


SVM
1.0 1.0 1.0
0.933333333333 0.944444444444 0.933333333333
1.0 1.0 1.0
1.0 1.0 1.0
1.0 1.0 1.0
0.933333333333 0.944444444444 0.933333333333
0.933333333333 0.944444444444 0.933333333333
1.0 1.0 1.0
1.0 1.0 1.0
1.0 1.0 1.0

Sum: 2.94333333333 


time 0.043044090271 

---

As of scikit-learn 0.19.0 the solution becomes much easier

from sklearn.model_selection import cross_validate
from sklearn.datasets import  load_iris
from sklearn.svm import SVC

iris = load_iris()
clf = SVC()
scoring = {'acc': 'accuracy',
           'prec_macro': 'precision_macro',
           'rec_micro': 'recall_macro'}
scores = cross_validate(clf, iris.data, iris.target, scoring=scoring,
                         cv=5, return_train_score=True)
print(scores.keys())
print(scores['test_acc'])  

Which gives:

['test_acc', 'score_time', 'train_acc', 'fit_time', 'test_rec_micro', 'train_rec_micro', 'train_prec_macro', 'test_prec_macro']
[ 0.96666667  1.          0.96666667  0.96666667  1.        ]