Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
304 views
in Technique[技术] by (71.8m points)

javascript - setTimeout not working inside forEach

I have a forEach that calls a function. There needs to be a delay between each time it is called. I've put it inside a setTimeout inside the forEach. It isn't respecting the timeout after the first wait. Instead it is waiting once, then running all at once. I've set the timeout to 5 seconds and I am using a console to confirm. 5 seconds of wait, then several foobar console logs all at once.

Why am I getting this behavior?

var index = 0;
json.objects.forEach(function(obj) {
    setTimeout(function(){
        console.log('foobar');
        self.insertDesignJsonObject(obj, index);
    }, 5000);
});
question from:https://stackoverflow.com/questions/37977602/settimeout-not-working-inside-foreach

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

What Jason said is totally correct in his answer but I thought I would give it a shot, to better clarify.

This is actually a classic closure problem. Typically it would look something like:

for(var i = 0; i < 10; i++){
    setTimeout(function(){
        console.log(i);
    },i * 1000)
}

The novice would expect the console to show:

0
(0 seconds pass...)
1
(1 second passes...)
2
(etc..)

But that just isn't the case! What you would actually see is the number 10 getting logged 10 times (1x per second)!

"Why does that happen?" Great question. Closure scope. The for loop above lacks closure scope because in javascript, only functions (lambdas) have closure scope!

See: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Closures

However! Your attempt would have achieved the desired output if you had tried this:

    json.objects.forEach(function(obj,index,collection) {
        setTimeout(function(){
            console.log('foobar');
            self.insertDesignJsonObject(obj, index);
        }, index * 5000);
    });

Because you have access to the "closur-ed" index variable - you can rely on its state being the expected state when the function (lambda) is invoked!

Other Resources:

How do JavaScript closures work?

http://javascript.info/tutorial/closures

http://code.tutsplus.com/tutorials/closures-front-to-back--net-24869


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...