linux - Sed to search regex pattern and remove line with above pattern

Question

this is my file.txt content. Here I'm trying to search pattern text: 'About' and remove items:[{ line with the command as below:

file.txt:

                items: [{
                        text: 'About',
                        handler: function() { TP.aboutWindow() }

Command: sed -n -i -E '/text: 'About'/{n; $p; x; d}; x; 1!p; ${x;p;}' file.txt

but it seems to be not working. Is there any way to make it work to remove line above pattern?

Thanks in advance.

question from:https://stackoverflow.com/questions/65931991/sed-to-search-regex-pattern-and-remove-line-with-above-pattern

Answer 1

You can use

sed -i "N;/
.*text: 'About'/"'!P;D' file.txt

Details:

• -i - file inplace replacement mode on
• N - opens a two-line window throughout the whole file (it reads the next line prepended with a newline into pattern space)
• .*text: 'About' matches a newline, then any text and then text: 'About'
• !P;D - if there is a match, do not print the first line, then delete the first line and repeat.