getting part of dictionary by value in python

Question

I have dictionary:

teamDictionary = {
1: {'name': 'Bob', 'team': 'A', 'status': 'Leave'},
2: {'name': 'George', 'team': 'C', 'status': 'Training'},
3: {'name': 'Sam', 'team': 'B', 'status': 'Travel'},
4: {'name': 'Phil', 'team': 'A', 'status': 'Leave'},
5: {'name': 'Georgia', 'team': 'C', 'status': 'Training'}
}

I need to get all smaller dictionary where team is C. My cod is:

team_leave = [teamDictionary[a] for a, b in teamDictionary.items() if b['team'] == 'C' ]

print(team_leave)

[{'name': 'George', 'team': 'C', 'status': 'Training'}, {'name': 'Georgia', 'team': 'C', 'status': 'Training'}]

But I need to get

{
    2: {'name': 'George', 'team': 'C', 'status': 'Training'},
    5: {'name': 'Georgia', 'team': 'C', 'status': 'Training'}
    }

How should I solve my problem?

question from:https://stackoverflow.com/questions/65949567/getting-part-of-dictionary-by-value-in-python

Answer 1

You can use a dict comprehension instead:

{k: d for k, d in teamDictionary.items() if d['team'] == 'C'}