python - How to round a value up WITH ndigits

Question

This question already has answers here: question from:https://stackoverflow.com/questions/65924305/how-to-round-a-value-up-with-ndigits

Answer 1

import math

def round(number, n):
    return math.ceil(number * math.pow(10, n+1))*(math.pow(10,-(n+1)))
    
print(round(1024, -3))

# 1100.0

A simple function like this would suffice, multiply by 10^(n+1), find the ceiling of that number, then multiply by 10^-n-1 (equivalent to dividing by 10^n+1).