Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
306 views
in Technique[技术] by (71.8m points)

arrays - Problem with converting string to integer

(I am very new to both coding and C.)

I want to check if the nr one string in "string argv" is one or more decimals and if it is convert it to an integer. I think I may need to iterate over the string but so far this code is not working. It says segmentation fault.

This is my code:

#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <math.h>
#include <stdlib.h>

int main (int argc, string argv [])
{

    //check command line
    if (argc == 2)
    {
        printf("success");
    }
    else
    {
        printf("Usage: ./caesar key.");
    }

    //validate number
    if (isdigit (argv[1]))
    {
        int x = atoi(argv[1]);
        printf("I is now %i
", x);
        return 0;
    }

    if (isalpha(argv[1]))
     {
        printf("Usage: ./caesar key
");
        return 1;
    }
}
question from:https://stackoverflow.com/questions/65906819/problem-with-converting-string-to-integer

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

main function takes (int argc, char *argv[]) parameters. argv is a pointer to pointer and argv[1] is a pointer to a char array too. You should send a character to isdigit and isalpha, not a pointer. You get a segmentation fault because of this probably.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

56.9k users

...