Getting index based on the first characters from a file in python using Regex

Question

I'm trying the get the index of a string in a file based on a regex which is looking for the value '01', but without success, can someone help me?

My Code

#!/bin/python

import os
import re

finalListFileTxt = 'C:\USER_ATU\Processing of TTSCOF00.IMG for file status\MSS_Sample\listOfFilesFromTtsFile.txt'
searchedIndexValue = []
with open(finalListFileTxt,"r") as arq:
    for linha in arq.readlines():
        pattern = r'^01$'
        searchedIndexValue = re.findall(pattern,linha)
        print(searchedIndexValue)

Actual Output

[]
[]
[]
[]
[]
[]

Input

That's a sample of the content of the file I'm using :

022413102101212003
022418102101212003
022423102101212003
022428102101212003
022433102101212003
022438102101212003
022443102101212003
012448102101212003
012453102101212003
021437032812202003
021442032812202003

What I'm looking for

My idea was to see in my list(searchedIndexValue) the row(not the content of the row) of each row starting with 01 in my file., the values : 8,9

question from:https://stackoverflow.com/questions/65903235/getting-index-based-on-the-first-characters-from-a-file-in-python-using-regex

Answer 1

@jasonharper is right. In addition to what he said, if you want to get the row numbers, you should make something like this:

import os
import re

finalListFileTxt = 'teste.txt'
searchedIndexValue = []
with open(finalListFileTxt,"r") as arq:
    for i,linha in enumerate(arq.readlines()):
        pattern = r'^01'
        if re.findall(pattern,linha):
            searchedIndexValue.append(i)
print(searchedIndexValue)

enumerate will iterate arq.readlines() and return a pair of linenumber and line.