Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
329 views
in Technique[技术] by (71.8m points)

list - Python 3: Get a nested dictionary value from using only one bracket []

I have a list of nested dictionaries and I need to be able to index the inside values by passing two keys simultaneously.

So if the data structure is like

value = {"dictkey1":{"dictkey2": x } }

then

y = value["dictkey1", "dictkey2"]

should allow me to access the value of x.

EDIT:

I have to check every parameter of a nested dictionary with an arbiraty amount of nests, so I found this solution that gives me the list with the dictionary keys:

def iter_leafs(self, d, keys=[]):
        for key, val in d.items():
            if isinstance(val, dict):
                yield from self.iter_leafs(val, keys + [key])
            else:
                yield keys + [key], val

this returns me a list like the one above, now, how can i reach a value with that list?

question from:https://stackoverflow.com/questions/65896554/python-3-get-a-nested-dictionary-value-from-using-only-one-bracket

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
Waitting for answers

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...