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python - Pythonesque way to compare adjacent elements in a list


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Try this code:

char_list = ['A', 'B', 'D', 'B', 'C', 'A', 'B']

count = 0
for index in range(0, len(char_list)-1):
    if char_list[index] == 'A' and char_list[index+1] == 'B':
        count += 1

print('count :', count)

Try this new one:

char_list = ['A', 'B', 'D', 'B', 'C', 'A', 'B', 'A', 'B']
prev_char = ''

count = 0
for char in char_list:
    if char == 'B' and prev_char == 'A':
        count += 1
    prev_char = char

print('count :', count)

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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