python - Split a string into groups of letters, ignoring whitespace

Question

This question already has answers here: question from:https://stackoverflow.com/questions/65869642/split-a-string-into-groups-of-letters-ignoring-whitespace

Answer 1

One option would be to strip all whitespace from the input, then use re.findall on the pattern .{1,4} to find all blocks of 4 (or however many available) characters. Then join that list together by space to generate the final output.

inp = "if you can dream it, you can do it"
parts = re.findall(r'.{1,4}', re.sub(r's+', '', inp))
output = ' '.join(parts)
print(output)

This prints:

ifyo ucan drea mit, youc ando it