python - Add tag attribute and description to Django rest framework

Question

Need help, there is serializers.py and it has the following class written in it:

class menu(serializers.ModelSerializer):
    a = serializers.CharField(default='http://localhost/1')

    class Meta:
        model = Object
        fields = ['a']

At the output, I get this line:

<a>http://localhost/1</a>

How to write the 'menu' class correctly so that the following construction is output:

<a href="http://localhost/1">Menu 1</a>

Thank you!

---

Update 1

I added the advice P. Naum into my code and now it looks like this:

class menu(serializers.ModelSerializer):
    a = serializers.SerializerMethodField(method_name='get_custom_a')

    class Meta:
        model = Object
        fields = ['a']

    def get_custom_a(self, obj):
        obj.a = 'http://localhost/1'
        return mark_safe('<a href="%s"/>' % obj.a)

And the conclusion is as follows:

<a><a href="http://localhost/1"/></a>

And I need it to be:

<a href="http://localhost/1"/>Menu name</a>

question from:https://stackoverflow.com/questions/65864846/add-tag-attribute-and-description-to-django-rest-framework

Answer 1

Not sure how you want the output to be, but assuming it's a simple API response, you may want to use SerializerMethodField described here

Assuming the url is a field named a in your model, it would look like this:

from django.utils.safestring import mark_safe
from rest_framework import serializers

class Menu(serializers.ModelSerializer):
    a = serializers.SerializerMethodField(method_name='get_custom_a')

    def get_custom_a(self, obj):
        return mark_safe('<a href="%s"/>' % (obj.a))

mark_safe is for the html output, you can learn about it here