In order to get it to work, the file name needs to be "java" and contain the file location in the arguments.
System.Diagnostics.Process clientProcess = new Process();
clientProcess.StartInfo.FileName = "java";
clientProcess.StartInfo.Arguments = @"-jar "+ jarPath +" " + argumentsFortheJarFile;
clientProcess.Start();
clientProcess.WaitForExit();
int code = clientProcess.ExitCode;
Taken from similar question here
Optional way using ArgumentList:
System.Diagnostics.Process clientProcess = new Process();
var info = new System.Diagnostics.ProcessStartInfo("java.exe")
{
ArgumentList = {
"-jar",
jarPath,
jarArgs
}
};
info.FileName = "java";
clientProcess.StartInfo = info;
clientProcess.Start();
clientProcess.WaitForExit();
int code = clientProcess.ExitCode;
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