You could use GROUP_CONCAT aggregated function to get all years into a single column, grouped by id
and ordered by rate
:
SELECT id, GROUP_CONCAT(year ORDER BY rate DESC) grouped_year
FROM yourtable
GROUP BY id
Result:
-----------------------------------------------------------
| ID | GROUPED_YEAR |
-----------------------------------------------------------
| p01 | 2006,2003,2008,2001,2007,2009,2002,2004,2005,2000 |
| p02 | 2001,2004,2002,2003,2000,2006,2007 |
-----------------------------------------------------------
And then you could use FIND_IN_SET, that returns the position of the first argument inside the second one, eg.
SELECT FIND_IN_SET('2006', '2006,2003,2008,2001,2007,2009,2002,2004,2005,2000');
1
SELECT FIND_IN_SET('2009', '2006,2003,2008,2001,2007,2009,2002,2004,2005,2000');
6
Using a combination of GROUP_CONCAT
and FIND_IN_SET
, and filtering by the position returned by find_in_set, you could then use this query that returns only the first 5 years for every id:
SELECT
yourtable.*
FROM
yourtable INNER JOIN (
SELECT
id,
GROUP_CONCAT(year ORDER BY rate DESC) grouped_year
FROM
yourtable
GROUP BY id) group_max
ON yourtable.id = group_max.id
AND FIND_IN_SET(year, grouped_year) BETWEEN 1 AND 5
ORDER BY
yourtable.id, yourtable.year DESC;
Please see fiddle here.
Please note that if more than one row can have the same rate, you should consider using GROUP_CONCAT(DISTINCT rate ORDER BY rate) on the rate column instead of the year column.
The maximum length of the string returned by GROUP_CONCAT is limited, so this works well if you need to select a few records for every group.