i am trying to cast a void** pointer to an int** 2D array in C
here is the code that i am trying to work with (with all the extraneous bits removed):
*assume that i have a data structure called graph with some
*element "void** graph" in it and some element "int order" */
void initialise_graph_data(graph_t *graph)
{
void **graph_data = NULL;
int (*matrix)[graph->order];
size_t size = (graph->order * graph->order) * sizeof(int);
graph_data = safe_malloc(size); /*safe malloc works fine*/
matrix = (int(*)[graph->order])graph_data;
graph->graph = graph_data;
}
when i compile that, it works fine, but gives me a warning that variable 'matrix' is set but not used. i dont really want to have to use the interim matrix variable because the function is just supposed to initialise the array, not put anything in it; but if i try to cast graph_data directly to an int** when i am assiging it to graph->graph like so:
graph->graph = (int(*)[graph->order])graph_data;
it gives me an assignment from incompatible pointer type warning.
am i just not casting it properly? does anyone have any suggestions as to how i can make it work without the interim "matrix" variable? or if not, what i can do with that variable so that it doesnt give me the warning that it is set but not used?
thanks
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